1/3x+3=4x

Solution for 1/3x+3=4x equation:

1/3x+3=4x

We move all terms to the left:

1/3x+3-(4x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-4x+1/3x+3=0

We multiply all the terms by the denominator


-4x*3x+3*3x+1=0

Wy multiply elements

-12x^2+9x+1=0

a = -12; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·(-12)·1
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{129}}{2*-12}=\frac{-9-\sqrt{129}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{129}}{2*-12}=\frac{-9+\sqrt{129}}{-24}
$