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1/3x+2=-3/4x-1
We move all terms to the left:
1/3x+2-(-3/4x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x-1)!=0We get rid of parentheses
x∈R
1/3x+3/4x+1+2=0
We calculate fractions
4x/12x^2+9x/12x^2+1+2=0
We add all the numbers together, and all the variables
4x/12x^2+9x/12x^2+3=0
We multiply all the terms by the denominator
4x+9x+3*12x^2=0
We add all the numbers together, and all the variables
13x+3*12x^2=0
Wy multiply elements
36x^2+13x=0
a = 36; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·36·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*36}=\frac{-26}{72} =-13/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*36}=\frac{0}{72} =0 $
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