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-5x^2+80=-20x-5
We move all terms to the left:
-5x^2+80-(-20x-5)=0
We get rid of parentheses
-5x^2+20x+5+80=0
We add all the numbers together, and all the variables
-5x^2+20x+85=0
a = -5; b = 20; c = +85;
Δ = b2-4ac
Δ = 202-4·(-5)·85
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{21}}{2*-5}=\frac{-20-10\sqrt{21}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{21}}{2*-5}=\frac{-20+10\sqrt{21}}{-10} $
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