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1/3s+2/9s=10
We move all terms to the left:
1/3s+2/9s-(10)=0
Domain of the equation: 3s!=0
s!=0/3
s!=0
s∈R
Domain of the equation: 9s!=0We calculate fractions
s!=0/9
s!=0
s∈R
9s/27s^2+6s/27s^2-10=0
We multiply all the terms by the denominator
9s+6s-10*27s^2=0
We add all the numbers together, and all the variables
15s-10*27s^2=0
Wy multiply elements
-270s^2+15s=0
a = -270; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-270)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-270}=\frac{-30}{-540} =1/18 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-270}=\frac{0}{-540} =0 $
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