x+2(3x+1)=12-4(x-2)

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Solution for x+2(3x+1)=12-4(x-2) equation: 



x+2(3x+1)=12-4(x-2)

We move all terms to the left:

x+2(3x+1)-(12-4(x-2))=0

We multiply parentheses

x+6x-(12-4(x-2))+2=0



We calculate terms in parentheses: -(12-4(x-2)), so:

12-4(x-2)

determiningTheFunctionDomain
-4(x-2)+12

We multiply parentheses

-4x+8+12

We add all the numbers together, and all the variables

-4x+20

Back to the equation:

-(-4x+20)



We add all the numbers together, and all the variables

7x-(-4x+20)+2=0

We get rid of parentheses

7x+4x-20+2=0

We add all the numbers together, and all the variables

11x-18=0

We move all terms containing x to the left, all other terms to the right

11x=18

x=18/11

x=1+7/11

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