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1/3p-3=1/24p
We move all terms to the left:
1/3p-3-(1/24p)=0
Domain of the equation: 3p!=0
p!=0/3
p!=0
p∈R
Domain of the equation: 24p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
1/3p-(+1/24p)-3=0
We get rid of parentheses
1/3p-1/24p-3=0
We calculate fractions
24p/72p^2+(-3p)/72p^2-3=0
We multiply all the terms by the denominator
24p+(-3p)-3*72p^2=0
Wy multiply elements
-216p^2+24p+(-3p)=0
We get rid of parentheses
-216p^2+24p-3p=0
We add all the numbers together, and all the variables
-216p^2+21p=0
a = -216; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-216)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-216}=\frac{-42}{-432} =7/72 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-216}=\frac{0}{-432} =0 $
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