(x+3)(x-3)=x(4x+5)

Solution for (x+3)(x-3)=x(4x+5) equation:

(x+3)(x-3)=x(4x+5)

We move all terms to the left:

(x+3)(x-3)-(x(4x+5))=0

We use the square of the difference formula

x^2-(x(4x+5))-9=0


We calculate terms in parentheses: -(x(4x+5)), so:

x(4x+5)

We multiply parentheses

4x^2+5x

Back to the equation:

-(4x^2+5x)


We get rid of parentheses

x^2-4x^2-5x-9=0

We add all the numbers together, and all the variables

-3x^2-5x-9=0

a = -3; b = -5; c = -9;
Δ = b2-4ac
Δ = -52-4·(-3)·(-9)
Δ = -83
Delta is less than zero, so there is no solution for the equation