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1/3n-1/9n=-1
We move all terms to the left:
1/3n-1/9n-(-1)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 9n!=0We add all the numbers together, and all the variables
n!=0/9
n!=0
n∈R
1/3n-1/9n+1=0
We calculate fractions
9n/27n^2+(-3n)/27n^2+1=0
We multiply all the terms by the denominator
9n+(-3n)+1*27n^2=0
Wy multiply elements
27n^2+9n+(-3n)=0
We get rid of parentheses
27n^2+9n-3n=0
We add all the numbers together, and all the variables
27n^2+6n=0
a = 27; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·27·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*27}=\frac{-12}{54} =-2/9 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*27}=\frac{0}{54} =0 $
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