If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/3k+17=12
We move all terms to the left:
1/3k+17-(12)=0
Domain of the equation: 3k!=0We add all the numbers together, and all the variables
k!=0/3
k!=0
k∈R
1/3k+5=0
We multiply all the terms by the denominator
5*3k+1=0
Wy multiply elements
15k+1=0
We move all terms containing k to the left, all other terms to the right
15k=-1
k=-1/15
k=-1/15
| 5(12−3p)=15p+6 | | 12x+-2=-6 | | 2x5=4x-9 | | 2/3(x+3)=3/4(x-2) | | 6x-300=100 | | x^2=2x | | 1/2x+6-1/x-2=0 | | -4s=-2s-10 | | 15+30x=150 | | 3(6x+1)=41-x | | 4(1/2x+2)=3x+12-x | | 9x+5+2x+8=68 | | 1-x1=-5 | | x/2+9=-2 | | x+4-11=7x+5 | | 2x+5+4x-9=8x-10 | | 6x+11-2x=-5 | | 2z+55=400 | | 1x1/4=6 | | 5x^2-45=360 | | x-5=15,x | | Y=5x=2 | | 7x-6(-2x+3)=37 | | 7+14m=-5+2m | | x-0.15=200 | | 3(j+5)=5(11+j) | | k-11.2=44 | | y=2.5(-2)-4 | | -2(n+20)=-2 | | 2x+18=15x-12x | | k=45k-17 | | 0.4(x+2)=3 |