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1/2x+6-1/x-2=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
1/2x-1/x+4=0
We calculate fractions
x/2x^2+(-2x)/2x^2+4=0
We multiply all the terms by the denominator
x+(-2x)+4*2x^2=0
Wy multiply elements
8x^2+x+(-2x)=0
We get rid of parentheses
8x^2+x-2x=0
We add all the numbers together, and all the variables
8x^2-1x=0
a = 8; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·8·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*8}=\frac{2}{16} =1/8 $
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