1/3b+2=12

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Solution for 1/3b+2=12 equation: 



1/3b+2=12

We move all terms to the left:

1/3b+2-(12)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

1/3b-10=0

We multiply all the terms by the denominator


-10*3b+1=0

Wy multiply elements

-30b+1=0

We move all terms containing b to the left, all other terms to the right

-30b=-1

b=-1/-30

b=1/30

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