1/4(8z+4)-6=1/2(10-8z)

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Solution for 1/4(8z+4)-6=1/2(10-8z) equation: 



1/4(8z+4)-6=1/2(10-8z)

We move all terms to the left:

1/4(8z+4)-6-(1/2(10-8z))=0



Domain of the equation: 4(8z+4)!=0

z∈R





Domain of the equation: 2(10-8z))!=0

z∈R



We add all the numbers together, and all the variables

1/4(8z+4)-(1/2(-8z+10))-6=0

We calculate fractions


(2z(-)/(4(8z+4)*2(-8z+10)))+(-4z8/(4(8z+4)*2(-8z+10)))-6=0



We calculate terms in parentheses: +(2z(-)/(4(8z+4)*2(-8z+10))), so:

2z(-)/(4(8z+4)*2(-8z+10))

We add all the numbers together, and all the variables

2z0/(4(8z+4)*2(-8z+10))

We multiply all the terms by the denominator


2z0

We add all the numbers together, and all the variables

2z

Back to the equation:

+(2z)





We calculate terms in parentheses: +(-4z8/(4(8z+4)*2(-8z+10))), so:

-4z8/(4(8z+4)*2(-8z+10))

We multiply all the terms by the denominator


-4z8

We add all the numbers together, and all the variables

-4z^8

We do not support ezpression: z^8

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