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1/39(6x-15)=1/2(10x-4)
We move all terms to the left:
1/39(6x-15)-(1/2(10x-4))=0
Domain of the equation: 39(6x-15)!=0
x∈R
Domain of the equation: 2(10x-4))!=0We calculate fractions
x∈R
(2x1/(39(6x-15)*2(10x-4)))+(-39x6/(39(6x-15)*2(10x-4)))=0
We calculate terms in parentheses: +(2x1/(39(6x-15)*2(10x-4))), so:
2x1/(39(6x-15)*2(10x-4))
We multiply all the terms by the denominator
2x1
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-39x6/(39(6x-15)*2(10x-4))), so:
-39x6/(39(6x-15)*2(10x-4))
We multiply all the terms by the denominator
-39x6
We add all the numbers together, and all the variables
-39x^6
We do not support expression: x^6
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