56x2=120

Solution for 56x2=120 equation:

56x^2=120

We move all terms to the left:

56x^2-(120)=0

a = 56; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·56·(-120)
Δ = 26880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26880}=\sqrt{256*105}=\sqrt{256}*\sqrt{105}=16\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{105}}{2*56}=\frac{0-16\sqrt{105}}{112}
=-\frac{16\sqrt{105}}{112}
=-\frac{\sqrt{105}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{105}}{2*56}=\frac{0+16\sqrt{105}}{112}
=\frac{16\sqrt{105}}{112}
=\frac{\sqrt{105}}{7}
$