1/3(y+4)+6=1/2(3y-5)+3

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Solution for 1/3(y+4)+6=1/2(3y-5)+3 equation: 



1/3(y+4)+6=1/2(3y-5)+3

We move all terms to the left:

1/3(y+4)+6-(1/2(3y-5)+3)=0



Domain of the equation: 3(y+4)!=0

y∈R





Domain of the equation: 2(3y-5)+3)!=0

y∈R



We calculate fractions


(2y3/(3(y+4)*2(3y-5))+(-3yy/(3(y+4)*2(3y-5))+6=0

We can not solve this equation

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