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1/3(y+1)+5=1/4(3y-2)-5
We move all terms to the left:
1/3(y+1)+5-(1/4(3y-2)-5)=0
Domain of the equation: 3(y+1)!=0
y∈R
Domain of the equation: 4(3y-2)-5)!=0We calculate fractions
y∈R
(4y3/(3(y+1)*4(3y-2))+(-3yy/(3(y+1)*4(3y-2))+5=0
We can not solve this equation
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