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1/3(x-5)=3x-2(x-1)+7/3
We move all terms to the left:
1/3(x-5)-(3x-2(x-1)+7/3)=0
Domain of the equation: 3(x-5)!=0We calculate fractions
x∈R
()/3x+(-(x+21xx)/3x=0
We add all the numbers together, and all the variables
()/3x+(-(+x+21xx)/3x=0
We multiply all the terms by the denominator
(-(+x+21xx)+()=0
We calculate terms in parentheses: +(-(+x+21xx)+(), so:We get rid of parentheses
-(+x+21xx)+(
We add all the numbers together, and all the variables
-(+x+21xx)
We get rid of parentheses
-x-21xx
We add all the numbers together, and all the variables
-1x-21xx
Back to the equation:
+(-1x-21xx)
-1x-21xx=0
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