1/5(x-4)=-4(x-1)+28/5

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Solution for 1/5(x-4)=-4(x-1)+28/5 equation: 



1/5(x-4)=-4(x-1)+28/5

We move all terms to the left:

1/5(x-4)-(-4(x-1)+28/5)=0



Domain of the equation: 5(x-4)!=0

x∈R



We calculate fractions


()/5x+(-(-4x+140xx)/5x=0

We multiply all the terms by the denominator


(-(-4x+140xx)+()=0



We calculate terms in parentheses: +(-(-4x+140xx)+(), so:

-(-4x+140xx)+(

We add all the numbers together, and all the variables

-(-4x+140xx)

We get rid of parentheses

4x-140xx

Back to the equation:

+(4x-140xx)



We add all the numbers together, and all the variables

(+4x-140xx)=0

We get rid of parentheses

4x-140xx=0

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