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1/3(x-5)+4=1/6(2-3x)+1
We move all terms to the left:
1/3(x-5)+4-(1/6(2-3x)+1)=0
Domain of the equation: 3(x-5)!=0
x∈R
Domain of the equation: 6(2-3x)+1)!=0We add all the numbers together, and all the variables
x∈R
1/3(x-5)-(1/6(-3x+2)+1)+4=0
We calculate fractions
(6x(-)/(3(x-5)*6(-3x+2))+(-3xx/(3(x-5)*6(-3x+2))+4=0
We can not solve this equation
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