(14/3)k+3k=46

Solution for (14/3)k+3k=46 equation:

(14/3)k+3k=46

We move all terms to the left:

(14/3)k+3k-(46)=0


Domain of the equation: 3)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(+14/3)k+3k-46=0

We add all the numbers together, and all the variables

3k+(+14/3)k-46=0

We multiply parentheses

14k^2+3k-46=0

a = 14; b = 3; c = -46;
Δ = b2-4ac
Δ = 32-4·14·(-46)
Δ = 2585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2585}}{2*14}=\frac{-3-\sqrt{2585}}{28}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2585}}{2*14}=\frac{-3+\sqrt{2585}}{28}
$