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1/3(x-3)-3=1/4(3x+2)
We move all terms to the left:
1/3(x-3)-3-(1/4(3x+2))=0
Domain of the equation: 3(x-3)!=0
x∈R
Domain of the equation: 4(3x+2))!=0We calculate fractions
x∈R
(4x3/(3(x-3)*4(3x+2)))+(-3xx/(3(x-3)*4(3x+2)))-3=0
We calculate terms in parentheses: +(4x3/(3(x-3)*4(3x+2))), so:
4x3/(3(x-3)*4(3x+2))
We multiply all the terms by the denominator
4x3
We add all the numbers together, and all the variables
4x^3
We do not support expression: x^3
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