1/3(x-12)=1/6(x-6)

Solution for 1/3(x-12)=1/6(x-6) equation:

1/3(x-12)=1/6(x-6)

We move all terms to the left:

1/3(x-12)-(1/6(x-6))=0


Domain of the equation: 3(x-12)!=0

x∈R



Domain of the equation: 6(x-6))!=0

x∈R


We calculate fractions


(6xx/(3(x-12)*6(x-6)))+(-3xx/(3(x-12)*6(x-6)))=0


We calculate terms in parentheses: +(6xx/(3(x-12)*6(x-6))), so:

6xx/(3(x-12)*6(x-6))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-3xx/(3(x-12)*6(x-6))), so:

-3xx/(3(x-12)*6(x-6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

6xx-3xx=0