X2+12x+43=(x+A)2+B

Solution for X2+12x+43=(x+A)2+B equation:

X2+12X+43=(X+)2+

We move all terms to the left:

X2+12X+43-((X+)2+)=0

We add all the numbers together, and all the variables

X2+12X-((+X)2+)+43=0

We add all the numbers together, and all the variables

X^2+12X-((+X)2+)+43=0


We calculate terms in parentheses: -((+X)2+), so:

(+X)2+

We add all the numbers together, and all the variables

(+X)2

We multiply parentheses

2X

Back to the equation:

-(2X)


We add all the numbers together, and all the variables

X^2+10X+43=0

a = 1; b = 10; c = +43;
Δ = b2-4ac
Δ = 102-4·1·43
Δ = -72
Delta is less than zero, so there is no solution for the equation