1/3(x-+3)=-x-4

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Solution for 1/3(x-+3)=-x-4 equation: 



1/3(x-+3)=-x-4

We move all terms to the left:

1/3(x-+3)-(-x-4)=0



Domain of the equation: 3(x-+3)!=0

x∈R



We add all the numbers together, and all the variables

1/3(+x)-(-1x-4)=0

We get rid of parentheses

1/3(+x)+1x+4=0

We multiply all the terms by the denominator


1x*3(+x)+4*3(+x)+1=0

Wy multiply elements

3x^2(++12x(++1=0

We use the square of the difference formula

3x^2(+12x(+1=0

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