2=(1/2)(7x-4)

Solution for 2=(1/2)(7x-4) equation:

2=(1/2)(7x-4)

We move all terms to the left:

2-((1/2)(7x-4))=0


Domain of the equation: 2)(7x-4))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/2)(7x-4))+2=0

We multiply parentheses ..

-((+7x^2+1/2*-4))+2=0

We multiply all the terms by the denominator


-((+7x^2+1+2*2*-4))=0


We calculate terms in parentheses: -((+7x^2+1+2*2*-4)), so:

(+7x^2+1+2*2*-4)

We get rid of parentheses

7x^2+1-4+2*2*

We add all the numbers together, and all the variables

7x^2

Back to the equation:

-(7x^2)


a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-14}=0$