1/3(x+6)=2/3(x-9)=

Solution for 1/3(x+6)=2/3(x-9)= equation:

1/3(x+6)=2/3(x-9)=

We move all terms to the left:

1/3(x+6)-(2/3(x-9))=0


Domain of the equation: 3(x+6)!=0

x∈R



Domain of the equation: 3(x-9))!=0

x∈R


We calculate fractions


(3xx/(3(x+6)*3(x-9)))+(-6xx/(3(x+6)*3(x-9)))=0


We calculate terms in parentheses: +(3xx/(3(x+6)*3(x-9))), so:

3xx/(3(x+6)*3(x-9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-6xx/(3(x+6)*3(x-9))), so:

-6xx/(3(x+6)*3(x-9))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)


We get rid of parentheses

3xx-6xx=0