12=-3(q+-10)

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Solution for 12=-3(q+-10) equation: 



12=-3(q+-10)

We move all terms to the left:

12-(-3(q+-10))=0

We add all the numbers together, and all the variables

-(-3(q-10))+12=0



We calculate terms in parentheses: -(-3(q-10)), so:

-3(q-10)

We multiply parentheses

-3q+30

Back to the equation:

-(-3q+30)



We get rid of parentheses

3q-30+12=0

We add all the numbers together, and all the variables

3q-18=0

We move all terms containing q to the left, all other terms to the right

3q=18

q=18/3

q=6

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