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1/3(x+5)+5/6(x-3)=x+1
We move all terms to the left:
1/3(x+5)+5/6(x-3)-(x+1)=0
Domain of the equation: 3(x+5)!=0
x∈R
Domain of the equation: 6(x-3)!=0We get rid of parentheses
x∈R
1/3(x+5)+5/6(x-3)-x-1=0
We calculate fractions
-x+(6xx/(3(x+5)*6(x-3))+(15xx/(3(x+5)*6(x-3))-1=0
We can not solve this equation
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