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1/2x=3x-3.5
We move all terms to the left:
1/2x-(3x-3.5)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-3x+3.5=0
We multiply all the terms by the denominator
-3x*2x+(3.5)*2x+1=0
We multiply parentheses
-3x*2x+7x+1=0
Wy multiply elements
-6x^2+7x+1=0
a = -6; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·(-6)·1
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*-6}=\frac{-7-\sqrt{73}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*-6}=\frac{-7+\sqrt{73}}{-12} $
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