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1/3(x+1)-4/5(x+2)=2x-1
We move all terms to the left:
1/3(x+1)-4/5(x+2)-(2x-1)=0
Domain of the equation: 3(x+1)!=0
x∈R
Domain of the equation: 5(x+2)!=0We get rid of parentheses
x∈R
1/3(x+1)-4/5(x+2)-2x+1=0
We calculate fractions
-2x+(5xx/(3(x+1)*5(x+2))+(-12xx/(3(x+1)*5(x+2))+1=0
We can not solve this equation
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