2(3r+4)-3(r=1)=11

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Solution for 2(3r+4)-3(r=1)=11 equation: 



2(3r+4)-3(r=1)=11

We move all terms to the left:

2(3r+4)-3(r-(1))=0

We multiply parentheses

6r-3r+8+3=0

We add all the numbers together, and all the variables

3r+11=0

We move all terms containing r to the left, all other terms to the right

3r=-11

r=-11/3

r=-3+2/3

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