1/3(p+22)=1/6(p-9)

Solution for 1/3(p+22)=1/6(p-9) equation:

1/3(p+22)=1/6(p-9)

We move all terms to the left:

1/3(p+22)-(1/6(p-9))=0


Domain of the equation: 3(p+22)!=0

p∈R



Domain of the equation: 6(p-9))!=0

p∈R


We calculate fractions


(6pp/(3(p+22)*6(p-9)))+(-3pp/(3(p+22)*6(p-9)))=0


We calculate terms in parentheses: +(6pp/(3(p+22)*6(p-9))), so:

6pp/(3(p+22)*6(p-9))

We multiply all the terms by the denominator


6pp

Back to the equation:

+(6pp)



We calculate terms in parentheses: +(-3pp/(3(p+22)*6(p-9))), so:

-3pp/(3(p+22)*6(p-9))

We multiply all the terms by the denominator


-3pp

Back to the equation:

+(-3pp)


We get rid of parentheses

6pp-3pp=0