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(2x+7)(2x+5)=72
We move all terms to the left:
(2x+7)(2x+5)-(72)=0
We multiply parentheses ..
(+4x^2+10x+14x+35)-72=0
We get rid of parentheses
4x^2+10x+14x+35-72=0
We add all the numbers together, and all the variables
4x^2+24x-37=0
a = 4; b = 24; c = -37;
Δ = b2-4ac
Δ = 242-4·4·(-37)
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{73}}{2*4}=\frac{-24-4\sqrt{73}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{73}}{2*4}=\frac{-24+4\sqrt{73}}{8} $
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