If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/3(9x-3)+x=7
We move all terms to the left:
1/3(9x-3)+x-(7)=0
Domain of the equation: 3(9x-3)!=0We add all the numbers together, and all the variables
x∈R
x+1/3(9x-3)-7=0
We multiply all the terms by the denominator
x*3(9x-3)-7*3(9x-3)+1=0
Wy multiply elements
3x^2(9-21x(9+1=0
| 4k=13=20 | | 4/5x-10=14 | | 8x+4x-14+1=59 | | 7=2x-40 | | 4s+8=-8-4s | | 3x+5x=135 | | (2x+39)+(x-15)+x=180 | | x-68=-3.5 | | 8+3k+k=-10+k | | (2x+39)+(x+15)+x=180 | | 7f-6=45 | | -2.2x-6.9x=221.0 | | 9b-1/2+5=4 | | 3(x+4)=7x+10-4x | | 2a-15=-5 | | 3(d-8)-5+9(d+2)=1 | | -5(x=7)=-5x+35 | | -2x+6=-6x+8 | | 11-2r+3=r | | 2x/3+1=3*x-3 | | 10x-5=-2x+1 | | 14y=63 | | 11n-16=6 | | 1.4y=6.3 | | -7(6+2x)+9=-68 | | 10z-z=-3+2z-2-16 | | -2.8x-9.5=223.9 | | 14x−8x=6 | | 8x+5-3x+1=31 | | A=8x+6B=4x+38 | | 6+2(3j-2=(1+j) | | 54=2(5x+7) |