3(d-8)-5+9(d+2)=1

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Solution for 3(d-8)-5+9(d+2)=1 equation: 



3(d-8)-5+9(d+2)=1

We move all terms to the left:

3(d-8)-5+9(d+2)-(1)=0

We add all the numbers together, and all the variables

3(d-8)+9(d+2)-6=0

We multiply parentheses

3d+9d-24+18-6=0

We add all the numbers together, and all the variables

12d-12=0

We move all terms containing d to the left, all other terms to the right

12d=12

d=12/12

d=1

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