1/3(9x+42)-5x=70

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Solution for 1/3(9x+42)-5x=70 equation: 



1/3(9x+42)-5x=70

We move all terms to the left:

1/3(9x+42)-5x-(70)=0



Domain of the equation: 3(9x+42)!=0

x∈R



We add all the numbers together, and all the variables

-5x+1/3(9x+42)-70=0

We multiply all the terms by the denominator


-5x*3(9x+42)-70*3(9x+42)+1=0

Wy multiply elements

-15x^2(9-210x(9+1=0

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