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1/3(9x+3)=2/5(10x+)
We move all terms to the left:
1/3(9x+3)-(2/5(10x+))=0
Domain of the equation: 3(9x+3)!=0
x∈R
Domain of the equation: 5(10x+))!=0We add all the numbers together, and all the variables
x∈R
1/3(9x+3)-(2/5(+10x))=0
We calculate fractions
(5x(+)/(3(9x+3)*5(+10x)))+(-6x9/(3(9x+3)*5(+10x)))=0
We calculate terms in parentheses: +(5x(+)/(3(9x+3)*5(+10x))), so:
5x(+)/(3(9x+3)*5(+10x))
We add all the numbers together, and all the variables
5x0/(3(9x+3)*5(+10x))
We multiply all the terms by the denominator
5x0
We add all the numbers together, and all the variables
5x
Back to the equation:
+(5x)
We calculate terms in parentheses: +(-6x9/(3(9x+3)*5(+10x))), so:
-6x9/(3(9x+3)*5(+10x))
We multiply all the terms by the denominator
-6x9
We add all the numbers together, and all the variables
-6x^9
We do not support expression: x^9
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