20=3(f+6)+14

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Solution for 20=3(f+6)+14 equation: 



20=3(f+6)+14

We move all terms to the left:

20-(3(f+6)+14)=0



We calculate terms in parentheses: -(3(f+6)+14), so:

3(f+6)+14

We multiply parentheses

3f+18+14

We add all the numbers together, and all the variables

3f+32

Back to the equation:

-(3f+32)



We get rid of parentheses

-3f-32+20=0

We add all the numbers together, and all the variables

-3f-12=0

We move all terms containing f to the left, all other terms to the right

-3f=12

f=12/-3

f=-4

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