1/3(9x+12)=1/2(12x-10)

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Solution for 1/3(9x+12)=1/2(12x-10) equation: 



1/3(9x+12)=1/2(12x-10)

We move all terms to the left:

1/3(9x+12)-(1/2(12x-10))=0



Domain of the equation: 3(9x+12)!=0

x∈R





Domain of the equation: 2(12x-10))!=0

x∈R



We calculate fractions


(2x1/(3(9x+12)*2(12x-10)))+(-3x9/(3(9x+12)*2(12x-10)))=0



We calculate terms in parentheses: +(2x1/(3(9x+12)*2(12x-10))), so:

2x1/(3(9x+12)*2(12x-10))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-3x9/(3(9x+12)*2(12x-10))), so:

-3x9/(3(9x+12)*2(12x-10))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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