5(v-2)-2=-3(-5v+2)-v

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Solution for 5(v-2)-2=-3(-5v+2)-v equation:



5(v-2)-2=-3(-5v+2)-v
We move all terms to the left:
5(v-2)-2-(-3(-5v+2)-v)=0
We multiply parentheses
5v-(-3(-5v+2)-v)-10-2=0
We calculate terms in parentheses: -(-3(-5v+2)-v), so:
-3(-5v+2)-v
We add all the numbers together, and all the variables
-1v-3(-5v+2)
We multiply parentheses
-1v+15v-6
We add all the numbers together, and all the variables
14v-6
Back to the equation:
-(14v-6)
We add all the numbers together, and all the variables
5v-(14v-6)-12=0
We get rid of parentheses
5v-14v+6-12=0
We add all the numbers together, and all the variables
-9v-6=0
We move all terms containing v to the left, all other terms to the right
-9v=6
v=6/-9
v=-2/3

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