1/3(9p-12)=17

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Solution for 1/3(9p-12)=17 equation: 



1/3(9p-12)=17

We move all terms to the left:

1/3(9p-12)-(17)=0



Domain of the equation: 3(9p-12)!=0

p∈R



We multiply all the terms by the denominator


-17*3(9p-12)+1=0

Wy multiply elements

-51p(9+1=0

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