3(x-4)2+7=3(x-4)2+7

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Solution for 3(x-4)2+7=3(x-4)2+7 equation: 



3(x-4)2+7=3(x-4)2+7

We move all terms to the left:

3(x-4)2+7-(3(x-4)2+7)=0

We multiply parentheses

6x-(3(x-4)2+7)-24+7=0



We calculate terms in parentheses: -(3(x-4)2+7), so:

3(x-4)2+7

We multiply parentheses

6x-24+7

We add all the numbers together, and all the variables

6x-17

Back to the equation:

-(6x-17)



We add all the numbers together, and all the variables

6x-(6x-17)-17=0

We get rid of parentheses

6x-6x+17-17=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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