1/3(9k+3)=3k+5

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Solution for 1/3(9k+3)=3k+5 equation: 



1/3(9k+3)=3k+5

We move all terms to the left:

1/3(9k+3)-(3k+5)=0



Domain of the equation: 3(9k+3)!=0

k∈R



We get rid of parentheses

1/3(9k+3)-3k-5=0

We multiply all the terms by the denominator


-3k*3(9k+3)-5*3(9k+3)+1=0

Wy multiply elements

-9k^2(9-15k(9+1=0

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