3x-2(x+4)+1=8+4(x-5)-7x

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Solution for 3x-2(x+4)+1=8+4(x-5)-7x equation: 



3x-2(x+4)+1=8+4(x-5)-7x

We move all terms to the left:

3x-2(x+4)+1-(8+4(x-5)-7x)=0

We multiply parentheses

3x-2x-(8+4(x-5)-7x)-8+1=0



We calculate terms in parentheses: -(8+4(x-5)-7x), so:

8+4(x-5)-7x

determiningTheFunctionDomain
4(x-5)-7x+8

We add all the numbers together, and all the variables

-7x+4(x-5)+8

We multiply parentheses

-7x+4x-20+8

We add all the numbers together, and all the variables

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

x-(-3x-12)-7=0

We get rid of parentheses

x+3x+12-7=0

We add all the numbers together, and all the variables

4x+5=0

We move all terms containing x to the left, all other terms to the right

4x=-5

x=-5/4

x=-1+1/4

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