1/3(9b+5)=-9

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Solution for 1/3(9b+5)=-9 equation: 



1/3(9b+5)=-9

We move all terms to the left:

1/3(9b+5)-(-9)=0



Domain of the equation: 3(9b+5)!=0

b∈R



We add all the numbers together, and all the variables

1/3(9b+5)+9=0

We multiply all the terms by the denominator


9*3(9b+5)+1=0

Wy multiply elements

27b(9+1=0

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