35/3x+x=35

Solution for 35/3x+x=35 equation:

35/3x+x=35

We move all terms to the left:

35/3x+x-(35)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x+35/3x-35=0

We multiply all the terms by the denominator


x*3x-35*3x+35=0

Wy multiply elements

3x^2-105x+35=0

a = 3; b = -105; c = +35;
Δ = b2-4ac
Δ = -1052-4·3·35
Δ = 10605
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{10605}}{2*3}=\frac{105-\sqrt{10605}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{10605}}{2*3}=\frac{105+\sqrt{10605}}{6}
$