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1/3(8-2c)=1/5(3c-5)
We move all terms to the left:
1/3(8-2c)-(1/5(3c-5))=0
Domain of the equation: 3(8-2c)!=0
c∈R
Domain of the equation: 5(3c-5))!=0We add all the numbers together, and all the variables
c∈R
1/3(-2c+8)-(1/5(3c-5))=0
We calculate fractions
(5c3/(3(-2c+8)*5(3c-5)))+(-3c0/(3(-2c+8)*5(3c-5)))=0
We calculate terms in parentheses: +(5c3/(3(-2c+8)*5(3c-5))), so:
5c3/(3(-2c+8)*5(3c-5))
We multiply all the terms by the denominator
5c3
We add all the numbers together, and all the variables
5c^3
We do not support ecpression: c^3
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