4x-2(x+3)=3(x-9)-4

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Solution for 4x-2(x+3)=3(x-9)-4 equation: 



4x-2(x+3)=3(x-9)-4

We move all terms to the left:

4x-2(x+3)-(3(x-9)-4)=0

We multiply parentheses

4x-2x-(3(x-9)-4)-6=0



We calculate terms in parentheses: -(3(x-9)-4), so:

3(x-9)-4

We multiply parentheses

3x-27-4

We add all the numbers together, and all the variables

3x-31

Back to the equation:

-(3x-31)



We add all the numbers together, and all the variables

2x-(3x-31)-6=0

We get rid of parentheses

2x-3x+31-6=0

We add all the numbers together, and all the variables

-1x+25=0

We move all terms containing x to the left, all other terms to the right

-x=-25

x=-25/-1

x=+25

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