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1/3(6x-5)-1=1/3-2(x+1)
We move all terms to the left:
1/3(6x-5)-1-(1/3-2(x+1))=0
Domain of the equation: 3(6x-5)!=0
x∈R
Domain of the equation: 3-2(x+1))!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
-2(x+1))!=-3
x∈R
(-2(x+1))+1*3)/52x+(-3x6/52x-1=0
We calculate terms in parentheses: +(-2(x+1)), so:We get rid of parentheses
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
+(-2x-2)
-2x+1*3)/52x+(-3x6/52x-2-1=0
We calculate fractions
We do not support expression: x^7
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