(20x-70)=(x2+30)

Solution for (20x-70)=(x2+30) equation:

(20x-70)=(x2+30)

We move all terms to the left:

(20x-70)-((x2+30))=0

We add all the numbers together, and all the variables

-((+x^2+30))+(20x-70)=0

We get rid of parentheses

-((+x^2+30))+20x-70=0


We calculate terms in parentheses: -((+x^2+30)), so:

(+x^2+30)

We get rid of parentheses

x^2+30

Back to the equation:

-(x^2+30)


We add all the numbers together, and all the variables

20x-(x^2+30)-70=0

We get rid of parentheses

-x^2+20x-30-70=0

We add all the numbers together, and all the variables

-1x^2+20x-100=0

a = -1; b = 20; c = -100;
Δ = b2-4ac
Δ = 202-4·(-1)·(-100)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-2}=+10$